Chemistry Molarity Solution: 38. A solution was prepared by mixing 50.00 mL of ...

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Solution: 38. A solution was prepared by mixing 50.00 mL of 0.100 M HNO 3 and 100.00 mL of 0.200 M HNO3. Calculate the molarity of the final solution of nitric acid.

Problem

38. A solution was prepared by mixing 50.00 mL of 0.100 M HNO 3 and 100.00 mL of 0.200 M HNO3. Calculate the molarity of the final solution of nitric acid.

Solution

We’re being asked to calculate the molarity (M) of nitric acid (HNO3) when 50.00 mL of 0.100 M HNO3 and 100.00 mL of 0.200 M HNO3 are mixed.


Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters). In other words:



We first need to determine the moles of HNO3 present in each initial solution. This is because we mixed two solutions containing HNO3 and the moles of HNO3 in the new solution is simply the sum of the moles of HNO3 in the original solutions.


Note that we need to convert mL to L since molarity is in mol/L.

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