Use the data given below to construct a Born-Haber cycle to determine the lattice energy of KBr.
K(s) → K(g) 89
K(g) → K+(g) + e- 419
½ Br2(l) → Br(g) 96
Br(g) + e- → Br-(g) -325
K(s) + ½ Br2(g) → KBr(s) -394
A) -885 kJ
B) -673 kJ
C) +367 kJ
D) -464 kJ
E) +246 kJ
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