Calculate the energy change when one 238U nucleus undergoes the reaction:
238U + n → 239Pu + 2β
The masses needed are 238U, 238.0508 amu; 239Pu, 239.0522 amu; n, 1.0087 amu.
a) -1.1 x 10-12 J
b) -1.5 x 10-10 J
c) -4.5 x 10-10 J
d) +1.5 x 10-12 J
e) +3.0 x 10-10 J
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