Problem: Calculate the energy change when one 238U nucleus undergoes the reaction:238U + n → 239Pu + 2βThe masses needed are 238U, 238.0508 amu; 239Pu, 239.0522 amu; n, 1.0087 amu. a) -1.1 x 10-12 Jb) -1.5 x 10-10 Jc) -4.5 x 10-10 Jd) +1.5 x 10-12 Je) +3.0 x 10-10 J

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Calculate the energy change when one 238U nucleus undergoes the reaction:

238U + n → 239Pu + 2β

The masses needed are 238U, 238.0508 amu; 239Pu, 239.0522 amu; n, 1.0087 amu.

a) -1.1 x 10-12 J

b) -1.5 x 10-10 J

c) -4.5 x 10-10 J

d) +1.5 x 10-12 J

e) +3.0 x 10-10 J