From the enthalpies of reaction
H2 (g) + F2 (g) → 2 HF (g) ΔH = -537 kJ
C (s) + 2 F2 (g) → CF4 (g) ΔH = -680 kJ
2 C (s) + 2 H2 (g) → C2H4 (g) ΔH = +52.3 kJ
calculate ΔH for the reaction of ethylene with F 2:
C2H4 (g) + 6 F2 (g) → 2 CF4 (g) + 4 HF (g)
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