Calculate the enthalpy change for the reaction
P4O6 (s) + 2 O2 (g) → P4O10 (s)
given the following enthalpies of reaction:
P4 (s) + 3 O2 (g) → P4O6 (s) ΔH = -1640.1 kJ
P4 (s) + 5 O2 (g) → P4O10 (s) ΔH = -2940.1 kJ
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