Problem: Consider the combustion of liquid methanol, CH 3OH (l):CH3OH (l) + 3/2 O2 (g) → CO2 (g) + 2 H2O (l)     ΔH = -726.5 kJ(a) What is the enthalpy change for the reverse reaction? Explain. 

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Consider the combustion of liquid methanol, CH 3OH (l):

CH3OH (l) + 3/2 O2 (g) → CO2 (g) + 2 H2O (l)     ΔH = -726.5 kJ

(a) What is the enthalpy change for the reverse reaction? Explain.

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