We will calculate the moles of O2 needed to react with 52.0 L of CH4 using mole to mole comparison.
Let’s first write a balanced reaction equation. We know that the reaction is a combustion reaction since CH4 is made of carbon and hydrogen and is combusted to form carbon dioxide and water as products.
• Reaction Equation: CH4 + O2 → CO2 + H2O
▪ C is balanced
▪ Balance H: CH4 + O2 → CO2 + 2 H2O
▪ Balance O: CH4 + 2 O2 → CO2 + 2 H2O
C 1 C 1
H 4 H
2 4 O 3 4
• Balanced reaction Equation: CH4 + 2 O2 → CO2 + 2 H2O
How many moles of O 2 (molar mass = 32.00 g/mol) are needed to react completely with 52.0 L of CH4(g) at STP to produce CO 2 and H2O? (molar mass (CH 4) = 16.04 g/mol)
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