Calculate the maximum electrical work that can be produced by this cell.
3 Co 2+ (aq) + 2 Cr (s) 2 Cr 3+ (aq) + 3 Co (s)
Given the following reduction potentials:
Cr 3+ + 3 e – → Cr E ° = - 0.74 Volts
Co 2+ (aq) + 2 e – → Co E ° = - 0.28 Volts
Faraday’s constant = 96,500 Coulombs / mole of electrons
a) – 800 kJ b) – 150 kJ c) – 266 kJ d) + 266 kJ
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