We are asked what is the daughter nucleus produced when neptunium-237 decays by alpha emission
Recall that in a nuclear reaction, the number of protons and neutrons are affected and the identity of the element changes. For alpha decay, an alpha particle (42α, atomic mass = 4, atomic number = 2) is formed as a product.
The incomplete nuclear equation is:
23793Np→ ___ + 42He
Atomic mass of the daughter nuclide:
237 = x + 4
x = 237 – 4 = 233
Identify the nuclide produced when neptunium-237 decays by alpha emission: 23793Np → 42He + ? Express your answer as an isotope using prescripts.
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