We will do the following steps to solve the problem:
Step 1: Calculate the mol of reactants
Step 2: Determine the limiting reactant
Step 3: Determine the mass of the precipitate
Step 4: calculate [NH4+] and [Cu2+] in solution
When 65.00 ml of 0.182 M CuBr2 is mixed with 55.00 ml of 0.147 M (NH4)2CrO4, the following reaction takes place: (NH4)2CrO4 (aq) + CuBr2 (aq) → CuCrO4 (s) + 2 NH4Br (aq)
Part A). What is the limiting reactant? Show work.
Part B) determine the mass in grams of precipitate that could theoretically be formed. Show work.
Part C) calculate [NH4+] and [Cu2+] in solution after this reaction is complete.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. You can view video lessons to learn Limiting Reagent. Or if you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.