🤓 Based on our data, we think this question is relevant for Professor Geissler's class at CAL.

Solution: Use the standard reduction potentials below to determine which element or ion is the best reducing agent. Pd2+ (aq) + 2 e –       →      Pd (s) E° = + 0.90 V 2 H+ (aq) + 2 e –        →        H2 (g) E° = 0.00 V Mn2+ (aq) + 2 e –       →      Mn (s) E° = – 1.18 V   a) Pd (s)             b) H + (aq)              c) Mn2+ (aq)              d) H2 (g)

Problem

Use the standard reduction potentials below to determine which element or ion is the best reducing agent.

Pd2+ (aq) + 2 e        →      Pd (s) E° = + 0.90 V

2 H+ (aq) + 2 e –        →        H2 (g) E° = 0.00 V

Mn2+ (aq) + 2 e        →      Mn (s) E° = – 1.18 V

 

a) Pd (s)             b) H + (aq)              c) Mn2+ (aq)              d) H2 (g)