# Problem: Hydrochloric acid (HCl) reacts with sodium carbonate (Na2CO3), forming sodium chloride (NaCl), water (H2O), and carbon dioxide (CO2). This equation is balanced as written: 2 HCl(aq) + Na2CO3 (aq) → 2 NaCl (aq) + H2O(l) + CO2(g) A 651-mL sample of unknown HCl solution reacts completely with Na2CO3 to form 12.1 g CO2. What was the concentration of the HCl solution? Express your answer to three significant figures and include the appropriate units.

###### FREE Expert Solution

2 HCl (aq) + Na2CO3 (aq) → 2 NaCl (aq) + H2O (l) + CO(g)

The flow of the calculation would be like this:

mass CO2(molar mass CO2) → mol CO2(mol-to-mol ratio) → mol HCl/volume HCl → molarity HCl

82% (266 ratings) ###### Problem Details

Hydrochloric acid (HCl) reacts with sodium carbonate (Na2CO3), forming sodium chloride (NaCl), water (H2O), and carbon dioxide (CO2). This equation is balanced as written: 2 HCl(aq) + Na2CO(aq) → 2 NaCl (aq) + H2O(l) + CO2(g)

A 651-mL sample of unknown HCl solution reacts completely with Na2CO3 to form 12.1 g CO2. What was the concentration of the HCl solution? Express your answer to three significant figures and include the appropriate units.