Determine the molecular and empirical formula of the following: (c) the reactive substance diborane, which has two boron atoms and six hydrogen atoms
Okay guys, so for this question we have to write the molecular formula and the empirical formula for diborane.
They tell us that diborane is composed of two boron atoms and six hydrogen atoms. Alright, so I'll try the molecular formula. Remember, your molecular formula is going to be your actual formula. They tell us what the actual formula is. They tell us that is it composed of two boron atoms and six hydrogen atoms. So our molecular formula is going to be B2H6. Now to write the empirical formula, we have to simplify the molecular formula. Right, because your empirical formula is your simplified version. We want to find the simplest whole number ratio of the moles. Okay, so you have to divide two and six and make them the simplest whole number possible.
Alright so let's divide both by two, this is going to give us BH3. Right, dividing by two. Can we further simplify BH3? No, because if you further simplify it we will have fractions and decimals which we do not want. This gives us a whole number but going further will not give us whole numbers.
So this is going to be your answer for your molecular formula and your empirical formula. Let's move on.