Strong Acid Strong Base Titrations Video Lessons

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Problem: Calculate the pH of the resulting solution if 30.0 mL of 0.300 M HCl(aq) is added to35.0 mL of 0.300 M NaOH(aq).

FREE Expert Solution

We’re being asked to determine the pH after addition of 30.0 mL of 0.300 M HCl(aq)

Let’s first write the balanced reaction between HCl and KOH:

▪ HCl → strong acid
▪ NaOH → (OH- with Group 1A ion) → strong base
▪ the reaction between a strong base and strong acid → no need to create an ICE chart

Balanced reaction:              HCl(aq) + NaOH(aq) → H2O(l) + NaCl(aq)

Let’s first calculate the initial amount of HCl in moles:

Recall:

molarity (M)=molL

moles HCl=0.30 mol HClL30 mL x 10-3 L1 mL

moles HCl= 0.009 mol HCl


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Problem Details

Calculate the pH of the resulting solution if 30.0 mL of 0.300 M HCl(aq) is added to

35.0 mL of 0.300 M NaOH(aq).

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