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Problem: What is the vapor pressure of mercury at 25°C if its enthalpy of vaporization is 59.1 kJ/mol? Note that the normal boiling point of mercury is 357°C.

FREE Expert Solution

For this problem, we can use the Clausius-Clapeyron Equation:


ln(P2P1)=-HvapR[1T2-1T1]


where:

P1 = vapor pressure at T1

P2 = vapor pressure at T2

ΔHvap = heat of vaporization (in J/mol)

R = gas constant (8.314 J/mol•K)

T1 and T2 = temperature (in K).


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Problem Details

What is the vapor pressure of mercury at 25°C if its enthalpy of vaporization is 59.1 kJ/mol? Note that the normal boiling point of mercury is 357°C.

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Our tutors have indicated that to solve this problem you will need to apply the Clausius-Clapeyron Equation concept. You can view video lessons to learn Clausius-Clapeyron Equation. Or if you need more Clausius-Clapeyron Equation practice, you can also practice Clausius-Clapeyron Equation practice problems.

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Based on our data, we think this problem is relevant for Professor Gailbreath's class at COFC.