Clausius-Clapeyron Equation Video Lessons

Concept:

# Problem: What is the vapor pressure of mercury at 25°C if its enthalpy of vaporization is 59.1 kJ/mol? Note that the normal boiling point of mercury is 357°C.

###### FREE Expert Solution

For this problem, we can use the Clausius-Clapeyron Equation:

$\overline{){\mathbf{ln}}\mathbf{\left(}\frac{{\mathbf{P}}_{\mathbf{2}}}{{\mathbf{P}}_{\mathbf{1}}}\mathbf{\right)}{\mathbf{=}}{\mathbf{-}}\frac{\mathbf{∆}{\mathbf{H}}_{\mathbf{vap}}}{\mathbf{R}}\mathbf{\left[}\frac{\mathbf{1}}{{\mathbf{T}}_{\mathbf{2}}}\mathbf{-}\frac{\mathbf{1}}{{\mathbf{T}}_{\mathbf{1}}}\mathbf{\right]}}$

where:

P1 = vapor pressure at T1

P2 = vapor pressure at T2

ΔHvap = heat of vaporization (in J/mol)

R = gas constant (8.314 J/mol•K)

T1 and T2 = temperature (in K).

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###### Problem Details

What is the vapor pressure of mercury at 25°C if its enthalpy of vaporization is 59.1 kJ/mol? Note that the normal boiling point of mercury is 357°C.

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Clausius-Clapeyron Equation concept. You can view video lessons to learn Clausius-Clapeyron Equation. Or if you need more Clausius-Clapeyron Equation practice, you can also practice Clausius-Clapeyron Equation practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Gailbreath's class at COFC.