# Problem: Determine the specific volume of superheated water vapor at 3.5 MPa and 450 oC based on the ideal-gas equation.

###### FREE Expert Solution

Specific volume is defined as the number of cubic meters occupied by one kilogram of matter

Ideal gas equation:

$\overline{){\mathbf{PV}}{\mathbf{=}}{\mathbf{nRT}}}$

P = pressure, atm
V = volume, L
n = moles, mol
R = gas constant = 0.08206 (L·atm)/(mol·K)
T = temperature, K

$\frac{\mathbf{P}\overline{)\mathbf{V}}}{\overline{)\mathbf{V}}}\mathbf{=}\frac{\mathbf{n}\mathbf{R}\mathbf{T}}{\mathbf{V}}\phantom{\rule{0ex}{0ex}}\mathbit{P}\mathbf{=}\frac{{\mathbf{n}}\mathbf{R}\mathbf{T}}{\mathbf{V}}$

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###### Problem Details

Determine the specific volume of superheated water vapor at 3.5 MPa and 450 oC based on the ideal-gas equation.