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Problem: The formula for cobalt(III) sulfite is Co2(SO3)3.a. How many grams of Co3+ are present in 1.64 moles of cobalt(III) sulfite?b. How many moles of SO32– ion are present in 1.47 grams of cobalt (III) sulfite?

FREE Expert Solution

Part A. The flow of the problem is

mol Co2(SO3)3 (mol-to-mol ratio) → mol Co3+ (molar mass Co3+) → mass Co3+


Given

  • mol Co2(SO3)3 = 1.64 mol
  • mol-to-mol ratio = 2 mol Co in every 1 mol Co2(SO3)3
  • molar mass Co = 58.93 g/mol


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Problem Details

The formula for cobalt(III) sulfite is Co2(SO3)3.

a. How many grams of Co3+ are present in 1.64 moles of cobalt(III) sulfite?

b. How many moles of SO32– ion are present in 1.47 grams of cobalt (III) sulfite?

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