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Problem: How many grams of (NH4)3PO4 are needed to make 0.250 L of 0.150 M (NH4)3PO4?

FREE Expert Solution

We’re being asked to calculate the mass of (NH4)3PO4 needed to make 0.250 L of 0.150 M solution.


Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters)

In other words:


Molarity(M)=moles of soluteLiters of solution


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Problem Details

How many grams of (NH4)3PO4 are needed to make 0.250 L of 0.150 M (NH4)3PO4?

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