We’re being asked to calculate the number of H atoms in 3.4 g of C12H22O11.
We can calculate the number of H atoms using the following steps:
mass C12H22O11 (molar mass) → moles C12H22O11 (mole-to-mole comparison) → moles H (Avogadro’s number) → atoms H
How many H atoms are in 3.4 g of C12H22O11?
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Based on our data, we think this problem is relevant for Professor Maslak's class at PSU.