The dissociation of HA is as follows:
HA(aq) + H2O(l) ⇌ H3O+(aq) + A–(aq)
From this, we can construct an ICE table. Remember that liquids are ignored in the ICE table and Ka expression.
The Ka expression for HA is:
If enough of a monoprotic acid is dissolved in water to produce a 0.0150 M solution with a pH of 6.05, what is the equilibrium constant for the acid?
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