Problem: The combustion of propane may be described by the chemical equation C3H8(g) + 5 O2(g) ⟶ 3 CO2(g) + 4 H2O(g) How many grams of O2(g) are needed to completely burn 86.6 g C3H8(g)?

FREE Expert Solution

We're being asked to calculate the grams of O2(g) needed to completely burn 86.6 g C3H8(g).

We're given the following balanced reaction:

C3H8(g) + 5 O2(g) ⟶ 3 CO2(g) + 4 H2O(g) 


From the balanced reaction:  1 mole of C3H8(g) reacts with 5 moles of O2(g)

 mass C3H8 (molar mass C3H8) → moles C3H8 (mole-to-mole comparison) → moles O2 (molar mass) → mass O2

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Problem Details

The combustion of propane may be described by the chemical equation 

C3H8(g) + 5 O2(g) ⟶ 3 CO2(g) + 4 H2O(g) 

How many grams of O2(g) are needed to completely burn 86.6 g C3H8(g)?

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