We’re being asked to determine the **calculate the free energy change for the reaction at 24 °C.**

In this case, we can determine **ΔS and use the relationship between ΔS and ΔH.**

We can calculate for **ΔS ** using the following equation:

$\overline{){\mathbf{\u2206}}{\mathbf{G}}{\mathbf{\xb0}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}{\mathbf{\u2206}}{\mathbf{H}}{\mathbf{\xb0}}{\mathbf{-}}{\mathbf{T}}{\mathbf{\u2206}}{\mathbf{S}}}$

2 Ca(s)+O_{2}(g) → 2 CaO(s) Δ*H*°rxn= -1269.8 kJ; Δ*S*°rxn= -364.6 J/K.

Calculate the free energy change for the reaction at 24 °C.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Gibbs Free Energy concept. You can view video lessons to learn Gibbs Free Energy. Or if you need more Gibbs Free Energy practice, you can also practice Gibbs Free Energy practice problems.