We’re being asked to **calculate the mass of Na _{2}SO_{4}**

Recall that ** molarity** is the ratio of the moles of solute and the volume of solution (in liters).

In other words:

$\overline{){\mathbf{Molarity}}{\mathbf{\left(}}{\mathbf{M}}{\mathbf{\right)}}{\mathbf{=}}\frac{\mathbf{moles}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solute}}{\mathbf{Liters}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solution}}}$

What mass of Na_{2}SO_{4} is needed to make 2.5 L of 2.0 M solution? (Na = 23 g; S = 32 g; O = 16 g)

a. 178 g

b. 710 g

c. 356 g

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