We’re being asked to calculate the percent ionization of a 0.250 M solution of benzoic acid.
Recall that the percent ionization is given by:
We know the initial concentration of benzoic acid, 0.250 M. We just need to find the concentration of H+ at equilibrium.
Since benzoic acid has a low Ka value, it’s a weak acid.
Remember that weak acids partially dissociate in water and that acids donate H+ to the base (water in this case).
The dissociation of benzoic acid is as follows:
C6H5COOH(aq) + H2O(l) ⇌ H3O+(aq) + C6H5COO–(aq); Ka = 6.3 x 10-5
Determine the percent ionization of a 0.250M solution of benzoic acid.
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