# Problem: 1. The reactant concentration in a zero-order reaction was 7.00×10−2 M after 160 s and 2.50×10−2 M after 345 s. What is the rate constant for this reaction?What was the initial reactant concentration for the reaction described in part one?2. The reactant concentration in a first-order reaction was 7.70×10−2 M after 50.0 s and 1.60×10−3 M after 85.0 s. What is the rate constant for this reaction?

###### FREE Expert Solution

For Part 1), we're being asked to determine the rate constant of a zero-order reaction.

The integrated rate law for a zero-order reaction is as follows:

$\overline{){\mathbf{\left[}\mathbf{A}\mathbf{\right]}}_{{\mathbf{t}}}{\mathbf{=}}{\mathbf{-}}{\mathbf{kt}}{\mathbf{+}}{{\mathbf{\left[}}{\mathbf{A}}{\mathbf{\right]}}}_{{\mathbf{0}}}}$

where:

[A]t = concentration at time t
k = rate constant
t = time
[A]0 = initial concentration

We can interpret this as:

79% (489 ratings)
###### Problem Details

1. The reactant concentration in a zero-order reaction was 7.00×10−2 M after 160 s and 2.50×10−2 M after 345 s. What is the rate constant for this reaction?

What was the initial reactant concentration for the reaction described in part one?

2. The reactant concentration in a first-order reaction was 7.70×10−2 M after 50.0 s and 1.60×10−3 M after 85.0 s. What is the rate constant for this reaction?