We're being asked to calculate the volume of 0.500 M H2SO4 is needed to react completely with 20.0 mL of 0.400 M LiOH.
The balanced reaction would be: H2SO4(aq) + 2 LiOH(aq) → Li2SO4(aq) + 2 H2O(l)
Calculate the volume of H2SO4:
molarity H2SO4 (volume) → moles H2SO4 (mole-to-mole comparison) → moles LiOH (molarity LiOH) → volume LiOH
Given:
molarity H2SO4 = 0.500 M
molarity LiOH = 0.400 M
volume LiOH solution = 25.00 mL → convert to L
What volume of 0.500 M H2SO4 is needed to react completely with 20.0 mL of 0.400 M LiOH?
A. 12.5 mL
B. 32.0 mL
C. 8.00 mL
D. 16.0 mL
E. 4.00 mL
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