We’re being asked to calculate the concentration of the barium ions (Ba2+) in a 0.750 M BaCl2 solution. Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters). In other words:
Since the BaCl2 is an ionic compound, it forms ions when dissociating in water. The dissociation of BaCl2 in water is as follows:
BaCl2(s) → Ba2+(aq) + 2 Cl–(aq)
What is the concentration of barium ions in a 0.750 M BaCl2 solution?
a. 0.375 M
b. 1.50 M
c. 2.25 M
d. 0.750 M
e. 0.160 M
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