PbCl4 dissociates as:
PbCl4 → Pb+4 + 4 Cl-
• the electron configuration of Pb is [Xe] 4f14 5d10 6s2 6p2
• the electron configuration of Pb4+ is [Xe] 4f14 5d10
The hybridization of the lead atom in PbCl4 is:
e) None of these choices are correct.
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