Problem: The hybridization of the lead atom in PbCl4 is:a) sp2b) dsp3c) dsp2d) d2sp3e) None of these choices are correct.

FREE Expert Solution

PbCl4 dissociates as:

   PbCl4       →        Pb+4        +        4 Cl-

• the electron configuration of Pb is [Xe] 4f14 5d10 6s2 6p2

• the electron configuration of Pb4+ is [Xe] 4f14 5d10 

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Problem Details

The hybridization of the lead atom in PbCl4 is:

a) sp2

b) dsp3

c) dsp2

d) d2sp3

e) None of these choices are correct.

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