We're being asked to determine the polarity of the Cl2XeF2 molecule.
For this problem, we need to do the following steps:
Step 1: Determine the central atom in this molecule.
Step 2: Calculate the total number of valence electrons present.
Step 3: Draw the Lewis structure for the molecule.
Step 4: Draw dipole arrows for each bond.
Step 5: Determine the polarity of the molecule.
Step 1: Xenon is less electronegative than chlorine and fluorine so xenon is the central atom.
Step 2: The total number of valence electrons present in Cl2XeF2 is:
Group Valence Electrons
Xe 8A 1 × 8 e– = 8 e–
F 7A 2 × 7 e– = 14 e–
Cl 7A 2 × 7 e– = 14 e–
Total: 36 valence e–
What is the polarity of the Cl2XeF2 molecule?
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Molecular Polarity concept. You can view video lessons to learn Molecular Polarity. Or if you need more Molecular Polarity practice, you can also practice Molecular Polarity practice problems.