Problem: 40.0 g of C6H6 are allowed to react with 75.0 g of Br2 according to the following balanced equation: C6H6 + Br2 → C6H5Br + HBre. If the actual yield C6H5Br was 59.7 g, what is the percent yield?

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Calculate C6H5Br from C6H6 :


Mass C6H6 (molar mass C6H6 )→ Moles of C6H6 (mole-to-mole comparison)  Moles of C6H5Br 


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Problem Details

40.0 g of C6H6 are allowed to react with 75.0 g of Br2 according to the following balanced equation: 


C6H6 + Br2 → C6H5Br + HBr

e. If the actual yield C6H5Br was 59.7 g, what is the percent yield?

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