40.0 g of C6H6 are allowed to react with 75.0 g of...

Question

40.0 g of C6H6 are allowed to react with 75.0 g of Br2 according to the following balanced equation: C6H6 + Br2 → C6H5Br + HBrc. What is the limiting reactant? (WHich one makes the least moles of C6H5Br)d. What is the theoretical yield of C6H5Br in grams?

Jules Bruno · Accepted Answer

Calculate C6H5Br from C6H6 :Mass C6H6 (molar mass C6H6 )→ Moles of C6H6 (mole-to-mole comparison) → Moles of C6H5Br [readmore]Molar mass of C6H6 : C6H6                    6 C × 12.01 g/mol C = 72.06 g/mol                            6 H × 1.01 g/mol H = 6.06 g/mol                          Sum = 78.12 g/molMole-to-mole comparison: The balanced chemical equation:C6H6 + Br2 → C6H5Br + HBrA mole-to-mole comparison will show that 1 mole of C6H6 form 1 mole of C6H5Br .40.0 g C6H6 ×1  mol C6H678.12  g C6H6× 1 mol C6H5Br1 mol C6H6 = 0.512 mol C6H5Br Calculate C6H5Br from Br2:Mass Br2(molar mass Br2 )→ Moles of Br2(mole-to-mole comparison) → Moles of C6H5Br Molar mass of Br2: Br2                       2 Br × 79.9 g/mol Br = 159.2 g/mol                             Mole-to-mole comparison: The balanced chemical equation:C6H6 + Br2 → C6H5Br + HBrA mole-to-mole comparison will show that 1 mole of Br2 form 1 mole of C6H5Br .75.0 g Br2 ×1  mol  Br2159.2 g Br2 × 1 mol C6H5Br1 mol  Br2 = 0.471 mol C6H5Br Br2 produces the least amount of product which makes it the limiting reactant.The limiting reactant produces the theoretical yield. Calculate mass of C6H5Br: Molar mass of C6H5Br : C6H5Br                   6 C × 12.01 g/mol C = 72.06 g/mol                                1 Br × 79.9 g/mol Br = 79.9 g/mol                                5 H × 1.01 g/mol H = 5.05 g/mol                          Sum = 157.01 g/mol0.471 mol C6H5Br ×157.01 g C6H5Br1  mol C6H5Br = 73.95 g C6H5Br The theoretical yield is 73.95 g C6H5Br .

Problem: 40.0 g of C6H6 are allowed to react with 75.0 g of Br2 according to the following balanced equation: C6H6 + Br2 → C6H5Br + HBrc. What is the limiting reactant? (WHich one makes the least moles of C6H5Br)d. What is the theoretical yield of C6H5Br in grams?

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Problem: 40.0 g of C6H6 are allowed to react with 75.0 g of Br2 according to the following balanced equation: C6H6 + Br2 → C6H5Br + HBrc. What is the limiting reactant? (WHich one makes the least moles of C6H5Br)d. What is the theoretical yield of C6H5Br in grams?

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