Calculate C6H5Br from C6H6 :
Mass C6H6 (molar mass C6H6 )→ Moles of C6H6 (mole-to-mole comparison) → Moles of C6H5Br
40.0 g of C6H6 are allowed to react with 75.0 g of Br2 according to the following balanced equation:
C6H6 + Br2 → C6H5Br + HBr
c. What is the limiting reactant? (WHich one makes the least moles of C6H5Br)
d. What is the theoretical yield of C6H5Br in grams?
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What scientific concept do you need to know in order to solve this problem?
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