Problem: 40.0 g of C6H6 are allowed to react with 75.0 g of Br2 according to the following balanced equation: C6H6 + Br2 → C6H5Br + HBrc. What is the limiting reactant? (WHich one makes the least moles of C6H5Br)d. What is the theoretical yield of C6H5Br in grams?

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Calculate C6H5Br from C6H6 :


Mass C6H6 (molar mass C6H6 )→ Moles of C6H6 (mole-to-mole comparison)  Moles of C6H5Br 


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Problem Details

40.0 g of C6H6 are allowed to react with 75.0 g of Br2 according to the following balanced equation: 


C6H6 + Br2 → C6H5Br + HBr

c. What is the limiting reactant? (WHich one makes the least moles of C6H5Br)

d. What is the theoretical yield of C6H5Br in grams?

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Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. You can view video lessons to learn Limiting Reagent. Or if you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.