Problem: 3.70 moles of sodium hydroxide are reacted with 2.00 moles of carbon dioxide according to the balanced equation: 2 NaOH(s) + CO2(g) → Na2CO3(s) + H2O(l)c. Which reactant makes the least amount of product (Na2CO3)?

FREE Expert Solution

Calculate Na2CO3 from NaOH:


Moles of NaOH (mole-to-mole comparison)  Moles of Na2CO3


Mole-to-mole comparison: The balanced chemical equation:

2 NaOH(s) + CO2(g) → Na2CO3(s) + H2O(l)


mole-to-mole comparison will show that 2 moles of NaOH form 1 mole of Na2CO3.


3.70 mol NaOH × 1 mol Na2CO32 mol NaOH 

= 1.85 mol Na2CO3


Calculate Na2CO3 from CO2:


Moles of CO(mole-to-mole comparison)  Moles of Na2CO3


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Problem Details

3.70 moles of sodium hydroxide are reacted with 2.00 moles of carbon dioxide according to the balanced equation: 


2 NaOH(s) + CO2(g) → Na2CO3(s) + H2O(l)

c. Which reactant makes the least amount of product (Na2CO3)?

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