Problem: Find the pH of a 0.013 M solution of HF. (The value of Ka for HF is 3.5×104)

FREE Expert Solution

We’re being asked to calculate pH of a 0.013 M solution of HF.


Since HA has a low Ka value, it’s a weak acid. 

Remember that weak acids partially dissociate in water and that acids donate H+ to the base (water in this case). 


The dissociation of HA is as follows:

HF(aq) + H2O(l)  H3O+(aq) + F(aq); Ka = 3.5×10-4


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Problem Details

Find the pH of a 0.013 M solution of HF. (The value of Ka for HF is 3.5×104)


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