We will use mole ratios to solve this problem
There is 8 moles of HF for every 1 mol of Na2SiO3
Na2SiO3(s) + 8 HF(aq) → H2SiF6(aq) + 2 NaF(aq) + 3 H2O(l)
a. How many moles of HF are needed to react with 0.305 mol of Na2SiO3?
b. How many grams of NaF form when 0.500 mol of HF react with excess Na2SiO3?
c. How many grams of Na2SiO3 can react with 0.856 g of HF
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