# Problem: Use Coulomb's Law to calculate the energy, in aJ, of a cadmium ion and a sulfide ion at their equilibrium ion-pair separation distance. An aJ is an attoJoule and equal to 1×10-18 J. Recall that Coulomb's Law is: E=Q1Q2/d where k is a proportionality constant equal to 231 aJ·pm, Q1 and Q2 are the charges of the two ions, and d is the distance between the two ions. Cd2+ has a radius of 95 pm and S2- has a radius of 184 pm.

###### FREE Expert Solution

Recall the formula for Coulomb's law:

where

k = 231 aJ·pm

Q1 and Q2 = charge of the ion

d = distance between the two ions

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###### Problem Details

Use Coulomb's Law to calculate the energy, in aJ, of a cadmium ion and a sulfide ion at their equilibrium ion-pair separation distance. An aJ is an attoJoule and equal to 1×10-18 J. Recall that Coulomb's Law is: E=Q1Q2/d where k is a proportionality constant equal to 231 aJ·pm, Q1 and Q2 are the charges of the two ions, and d is the distance between the two ions. Cd2+ has a radius of 95 pm and S2- has a radius of 184 pm.