Problem: Ammonia, NH3, reacts with hypochlorite ion, OCl–, to produce hydrazine, N2H4. How many grams of hydrazine are produced from 115.0 g NH3 if the reaction has a 81.5% yield?  2 NH3 + OCl– → N2H­4 + Cl– + H2O

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Ammonia, NH3, reacts with hypochlorite ion, OCl, to produce hydrazine, N2H4. How many grams of hydrazine are produced from 115.0 g NH3 if the reaction has a 81.5% yield?  

2 NH3 + OCl → N24 + Cl + H2O

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