Since we have the mass and the temperature and pressure (STP), we’re going to use the ideal gas equation to calculate the volume of the gas

**STP** means Standard Temperature and Pressure where:

P = 1 atm

T = 0°C = 273.15 K

Recall that the ideal gas law is given by

$\overline{){\mathbf{PV}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}{\mathbf{nRT}}}$

rearrange the equation to derive volume

$\frac{\overline{)\mathbf{P}}\mathbf{V}}{\overline{)\mathbf{P}}}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{nRT}}{\mathbf{P}}\phantom{\rule{0ex}{0ex}}\mathbf{V}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{nRT}}{\mathbf{P}}$

Calculate the volume of each gas sample at STP

52.0 mg Cl_{2}.

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