Arrange the following substances in order of decre...

Question

Arrange the following substances in order of decreasing magnitude of lattice energy. Rank from largest to smallest magnitude of lattice energy. To rank items as equivalent, overlap them.

CaO, BaO, KCl, RbBr

Jules Bruno · Accepted Answer

We are being asked to rank the following in order of decreasing magnitude of lattice energy: CaO, BaO, KCl, RbBrThe lattice energy can be estimated using:Lattice energy = |cation charge·anion charge|cation radius + anion radius[readmore]For CaO:CaGroup 2A → +2 charge → Ba2+Period = 4OGroup 6A → -2 charge → O2-Period = 2The lattice energy of CaO isLattice energy = |+2·-2|4+2 = 0.67For BaO:BaGroup 2A → +2 charge → Ba2+Period = 6OGroup 6A → -2 charge → O2-Period = 2The lattice energy of BaO isLattice energy = |+2·-2|6+2 = 0.5For KClKGroup 1A → +1 charge → K+Period = 4ClGroup 7A → -1 charge → Cl-Period = 3The lattice energy of KCl isLattice energy = |+1·-1|4+3 = 0.14For RbBrRbGroup 1A → +1 charge → Rb+Period = 5BrGroup 7A → -1 charge → Br-Period = 4The lattice energy of RbBr isLattice energy = |+1·-1|5+4 = 0.11Answer: The rank of the following in order of decreasing magnitude of lattice energy is CaO > BaO > KCl > RbBr

Problem: Arrange the following substances in order of decreasing magnitude of lattice energy. Rank from largest to smallest magnitude of lattice energy. To rank items as equivalent, overlap them.CaO, BaO, KCl, RbBr

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Problem: Arrange the following substances in order of decreasing magnitude of lattice energy. Rank from largest to smallest magnitude of lattice energy. To rank items as equivalent, overlap them.CaO, BaO, KCl, RbBr

FREE Expert Solution

Problem Details

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