Problem: Balance the following redox reaction by inserting the appropriate coefficients.H2O + Se + Cd2+ → Cd + SeO32- + H+

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We are being asked to balance the given redox reaction occurring in an acidic solution

We will assume that the reaction is under acidic condition unless stated otherwise. When balancing redox reactions under acidic conditions, we will use the following steps.

Step 1: Separate the whole reaction into half-reactions
Step 2: Balance the non-hydrogen and non-oxygen elements first
Step 3: Balance oxygen by adding H2O to the side that needs oxygen (1 O: 1 H2O)
Step 4: Balance hydrogen by adding H+ to the side that needs hydrogen (1 H: 1 H+)
Step 5: Balance the charges: add electrons to the more positive side (or less negative side)
Step 6: Balance electrons on the two half-reactions
Step 7: Get the overall reaction by adding the two reaction


Given reaction: H2O + Se + Cd2+ → Cd + SeO32- + H+

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Problem Details

Balance the following redox reaction by inserting the appropriate coefficients.

H2O + Se + Cd2+ → Cd + SeO32- + H+

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