# Problem: A. Write a net ionic equation for all chemical reactions below. (Hint: it is possible for the net ionic equation to be the same as the molecular equation. A complex ion that is in solution is molecular in nature because units are coordinate covalently bonded together.)1. Cu(s) + 4 HNO3(aq) → Cu(NO3)2 (aq) + 2 NO2 (g) + 2 H2O(l)2. Cu(NO3)2 (aq) + 2 NaOH (aq) → Cu(OH)2(s) + 2 NaNO3(aq)3. Cu(OH)2(s) → CuO(s) + H2O(l)4. CuO(s) + H2SO4(aq) → CuSO4(aq) + H2O(l)5. CuSO4(aq) + Zn(s) → Cu(s) + ZnSO4(aq)6. Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2(g)7. Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)

###### FREE Expert Solution

We are being asked to write the net ionic equation of the following reactions. We will do the following steps:

Step 1: Write the total ionic equation

soluble ionic compounds separate and become ions in the chemical equation
compounds that are aqueous can break up into ions
insoluble compounds (solids, liquids, and gases) will not break up the solution

Step 2: Write the net ionic equation

Remove spectator ions

• species present on both reactant and product side
• they should have the same state, same phase, same charge
these species are not really participating in the reaction and they are “floating around” the solution

80% (249 ratings) ###### Problem Details

A. Write a net ionic equation for all chemical reactions below. (Hint: it is possible for the net ionic equation to be the same as the molecular equation. A complex ion that is in solution is molecular in nature because units are coordinate covalently bonded together.)

1. Cu(s) + 4 HNO3(aq) → Cu(NO3)2 (aq) + 2 NO2 (g) + 2 H2O(l)

2. Cu(NO3)2 (aq) + 2 NaOH (aq) → Cu(OH)2(s) + 2 NaNO3(aq)

3. Cu(OH)2(s) → CuO(s) + H2O(l)

4. CuO(s) + H2SO4(aq) → CuSO4(aq) + H2O(l)

5. CuSO4(aq) + Zn(s) → Cu(s) + ZnSO4(aq)

6. Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2(g)

7. Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)