Problem: A. Write a net ionic equation for all chemical reactions below. (Hint: it is possible for the net ionic equation to be the same as the molecular equation. A complex ion that is in solution is molecular in nature because units are coordinate covalently bonded together.)1. Cu(s) + 4 HNO3(aq) → Cu(NO3)2 (aq) + 2 NO2 (g) + 2 H2O(l)2. Cu(NO3)2 (aq) + 2 NaOH (aq) → Cu(OH)2(s) + 2 NaNO3(aq)3. Cu(OH)2(s) → CuO(s) + H2O(l)4. CuO(s) + H2SO4(aq) → CuSO4(aq) + H2O(l)5. CuSO4(aq) + Zn(s) → Cu(s) + ZnSO4(aq)6. Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2(g)7. Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)

We are being asked to write the net ionic equation of the following reactions. We will do the following steps:

Step 1: Write the total ionic equation

•soluble ionic compounds separate and become ions in the chemical equation
• compounds that are aqueous can break up into ions
• insoluble compounds (solids, liquids, and gases) will not break up the solution

Step 2: Write the net ionic equation

Remove spectator ions

• species present on both reactant and product side
• they should have the same state, same phase, same charge
  these species are not really participating in the reaction and they are “floating around” the solution