We're being asked to calculate the equivalents present in 2.5 g of Al^{3+}.

**Normality (N)** represents the number of equivalents per liter of solution.

$\overline{){\mathbf{N}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{equivalents}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solution}}{\mathbf{L}\mathbf{}\mathbf{solution}}}$

$\overline{){\mathbf{equivalents}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}{\mathbf{n}}{\mathbf{\times}}{\mathbf{moles}}}$

How many equivalents are present in 2.5 g of Al^{3+}?

A. 7.5 eq

B. 0.28 eq

C. 0.10 eq

D. 0.18 eq

E. 1.5 eq

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Normality & Equivalent Weight concept. If you need more Normality & Equivalent Weight practice, you can also practice Normality & Equivalent Weight practice problems.