How many equivalents are present in 2.5 g of Al3+?...

Question

How many equivalents are present in 2.5 g of Al3+?A. 7.5 eqB. 0.28 eqC. 0.10 eqD. 0.18 eqE. 1.5 eq

Jules Bruno · Accepted Answer

We're being asked to calculate the equivalents present in 2.5 g of Al3+.Normality (N) represents the number of equivalents per liter of solution.N = equivalents of solutionL solutionequivalents = n×moles[readmore]for an acid:                          n = # of acidic hydrogensfor a base:                           n = # of OH-for a redox reaction:          n = # of electrons transferredmass Al3+ = 2.5 gmolar mass Al = 26.98 g/molAl → Al3+ +3 charge means it lost 3 electrons:  n = 3Calculate moles Al3+:moles Al3+=2.5 g Al3+×1 mol Al3+26.98 g Al3+moles Al3+ = 0.09266 mol Al3+Calculate equivalents:equivalents = n×molesequivalents=3×0.09266equivalents = 0.278 eq Al3+The equivalents present in 2.5 g of Al3+ is 0.278 eq.

Problem: How many equivalents are present in 2.5 g of Al3+?A. 7.5 eqB. 0.28 eqC. 0.10 eqD. 0.18 eqE. 1.5 eq

FREE Expert Solution

Problem Details

Problem: How many equivalents are present in 2.5 g of Al3+?A. 7.5 eqB. 0.28 eqC. 0.10 eqD. 0.18 eqE. 1.5 eq

FREE Expert Solution

Problem Details

Sign up for free to watch this video!