Problem: How many equivalents are present in 2.5 g of Al3+?A. 7.5 eqB. 0.28 eqC. 0.10 eqD. 0.18 eqE. 1.5 eq

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We're being asked to calculate the equivalents present in 2.5 g of Al3+.


Normality (N) represents the number of equivalents per liter of solution.

N = equivalents of solutionL solution

equivalents = n×moles

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Problem Details

How many equivalents are present in 2.5 g of Al3+?

A. 7.5 eq

B. 0.28 eq

C. 0.10 eq

D. 0.18 eq

E. 1.5 eq

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What scientific concept do you need to know in order to solve this problem?

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