We’re being asked to determine the pH after the addition of 50 mL of HCl
Let’s first write the balanced reaction between HCl and KOH:
▪ HCl → strong oxyacid
▪ KOH → (OH- with Group 1A ion) → strong base
▪ the reaction between a strong base and strong acid → no need to create an ICE chart
Balanced reaction: HCl(aq) + KOH(aq) → H2O(l) + KCl(aq)
Let’s first calculate the initial amount of KOH in moles:
moles KOH = 0.0056 mol KOH
Calculate the pH for each of the following cases in the titration of 35.0 mL of 0.160 M KOH(aq), with 0.160 M HCl(aq).
(f) after the addition of 50.0 mL of HCl
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