We’re being asked to determine the pH after the addition of 41.5 mL of HCl
Let’s first write the balanced reaction between HCl and KOH:
▪ HCl → strong oxyacid
▪ KOH → (OH- with Group 1A ion) → strong base
▪ the reaction between a strong base and strong acid → no need to create an ICE chart
Balanced reaction: HCl(aq) + KOH(aq) → H2O(l) + KCl(aq)
Let’s first calculate the initial amount of KOH in moles:
moles KOH = 0.0056 mol KOH
Calculate the pH for each of the following cases in the titration of 35.0 mL of 0.160 M KOH(aq), with 0.160 M HCl(aq).
(e) after the addition of 41.5 mL of HCl
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Strong Acid Strong Base Titrations concept. You can view video lessons to learn Strong Acid Strong Base Titrations. Or if you need more Strong Acid Strong Base Titrations practice, you can also practice Strong Acid Strong Base Titrations practice problems.