Strong Acid Strong Base Titrations Video Lessons

Concept

# Problem: Calculate the pH for each of the following cases in the titration of 35.0 mL of 0.160 M KOH(aq), with 0.160 M HCl(aq).(c) after addition of 20.5 mL of HCl

###### FREE Expert Solution

We’re being asked to determine the pH after addition of 20.5 mL of HCl

Let’s first write the balanced reaction between HCl and KOH:

▪ HCl → strong oxyacid
▪ KOH → (OH- with Group 1A ion) → strong base
▪ the reaction between a strong base and strong acid → no need to create an ICE chart

Balanced reaction:              HCl(aq) + KOH(aq) → H2O(l) + KCl(aq)

Let’s first calculate the initial amount of KOH in moles:

Recall:

moles KOH = 0.0056 mol KOH

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###### Problem Details

Calculate the pH for each of the following cases in the titration of 35.0 mL of 0.160 M KOH(aq), with 0.160 M HCl(aq).

(c) after addition of 20.5 mL of HCl

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