Problem: Given that Ka for HCN is 4.9x10-10 calculate Kb for CN- 

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We are asked to find Kb for CN-. CN- is the conjugate base of the weak acid HCN

HCN              +     H2O      ⇌                H3O+    +     CN-
(weak base)              (acid)             (conjugate acid)     (conjugate base) 

Hence, the Kb of CN- can be calculated from the Ka of HCN. Ka and Kb are related by the autoionization constant of water (Kwby the following equation:

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Given that Ka for HCN is 4.9x10-10 calculate Kb for CN

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