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**Problem**: What is the maximum number of electrons in an atom that can have the following quantum numbers?n = 4, l = 1, ml = 0

###### FREE Expert Solution

###### FREE Expert Solution

In this problem, we are being asked to determine the **maximum number of electrons in an atom that has a quantum number of n = 4, ℓ = l, and ml = 0**.

**Next, let’s define and determine the possible values of the quantum numbers:**

• the **principal quantum number**** ****→**** **energy level in orbitals and its value could be **any positive integer **starting from 1 to infinity

• **angular momentum quantum number (ℓ)**** ****→ ****(l) has to be at least 1 less than n, **range of values from** 0 up to (n-1)**

▪ Each **ℓ value **corresponds to a **subshell**:

**ℓ**** = 0** → s subshell**ℓ**** = 1** → p subshell **ℓ**** = 2** → d subshell**ℓ**** = 3** → f subshell

• **magnetic quantum number (m _{ℓ})**

**→**range of values from

**-**

**ℓ**

**to +**

**ℓ**

▪ The **m _{ℓ} values **(for each ℓ) represent

**electron orbitals**for the subshell:

**s subshell**→ 1 orbital**p subshell**→ 3 orbitals**d subshell** → 5 orbitals**f subshell** → 7 orbitals

###### Problem Details

What is the maximum number of electrons in an atom that can have the following quantum numbers?

n = 4, l = 1, ml = 0

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Quantum Numbers: Number of Electrons concept. You can view video lessons to learn Quantum Numbers: Number of Electrons Or if you need more Quantum Numbers: Number of Electrons practice, you can also practice Quantum Numbers: Number of Electrons practice problems .

How long does this problem take to solve?

Our expert Chemistry tutor, Shreya took 2 minutes to solve this problem. You can follow their steps in the video explanation above.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Hove's class at RUTGERS.