Problem: A solution containing a mixture of metal cations was treated with dilute HCl and no precipitate formed. Next, H2S was bubbled through the acidic solution. A precipitate formed and was filtered off. Then, the pH was raised to about 8 and H2S was again bubbled through the solution. A precipitate again formed and was filtered off. Finally, the solution was treated with a sodium carbonate solution, which resulted in no precipitation. Which metal ions were definitely present, which were definitely absent, and which may or may not have been present in the original mixture?Hg2+, Ba2+, Zn2+, Fe2+, Cr3+, Li+, Mg2+, Pb2+,Hg22+, Ag+, Cd2+, Sn4+, Sb3+

FREE Expert Solution

Determine the present cations by elimination through each step. 

Hg2+, Ba2+, Zn2+, Fe2+, Cr3+, Li+, Mg2+, Pb2+,Hg22+, Ag+, Cd2+, Sn4+, Sb3+


Adding HCl:

  • HCl → H+ + Cl-
  • Cl- are soluble except when paired with Ag+, Pb2+, Cu+, Hg22+
  • No precipitate formed so the mentioned exceptions to being soluble are all out. 

Add to definitely not present:

  • Definitely not present: Ag+, Pb2+, Hg22+
  • Remaining: Hg2+, Ba2+, Zn2+, Fe2+, Cr3+, Li+, Mg2+, Cd2+, Sn4+, Sb3+


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Problem Details

A solution containing a mixture of metal cations was treated with dilute HCl and no precipitate formed. Next, H2S was bubbled through the acidic solution. A precipitate formed and was filtered off. Then, the pH was raised to about 8 and H2S was again bubbled through the solution. A precipitate again formed and was filtered off. Finally, the solution was treated with a sodium carbonate solution, which resulted in no precipitation. Which metal ions were definitely present, which were definitely absent, and which may or may not have been present in the original mixture?

Hg2+, Ba2+, Zn2+, Fe2+, Cr3+, Li+, Mg2+, Pb2+,Hg22+, Ag+, Cd2+, Sn4+, Sb3+

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