Problem: Calculate the molar solubility of barium fluoride in each liquid or solution. a. pure water b. 0.10 M Ba(NO3)2 c. 0.15 M NaF

FREE Expert Solution

Since barium fluoride (BaF2) is an ionic compound, it forms ions when dissociating in water. 

The dissociation of BaF2 in water is as follows:

The fluoride ion, F, has a charge of –1. Barium is in Group 2A so it’s charge is +2:
BaF2(s) → Ba2+(aq) + 2 F(aq)

Ksp of BaF2 = 1.0x10–6 (can be found in books or online)


a. pure water 

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Problem Details

Calculate the molar solubility of barium fluoride in each liquid or solution. 

a. pure water 

b. 0.10 M Ba(NO3)2 

c. 0.15 M NaF

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