Hey there! We have to arrange the solutions of KNO_{3}, Li_{3}PO_{4}, Na_{2}SO_{4}, SnCl_{4} by their freezing points.

**Freezing point depression **is the decrease in freezing point of solution, when a solute is added to a solvent. It is calculated using this formula:

$\overline{){\mathbf{\u2206}}{{\mathbf{T}}}_{{\mathbf{f}}}{\mathbf{=}}{\mathbf{i}}{\mathbf{\xb7}}{{\mathbf{K}}}_{{\mathbf{f}}}{\mathbf{\xb7}}{\mathbf{m}}}$

**Where:**

ΔT_{f} = change in freezing point

i = van ‘t Hoff factor

K_{f} =freezing point depression constant

m = molality

Since, all the solutions have equal concentrations, we just have to look at the van ‘t Hoff factor to determine the freezing point depression.

Assuming equal concentrations, rank these aqueous solutions by their freezing point. From highest freezing point to lowest freezing point. KNO_{3}, Li_{3}PO_{4}, Na_{2}_{}SO_{4}, SnCl_{4}

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