# Problem: Assuming equal concentrations, rank these aqueous solutions by their freezing point. From highest freezing point to lowest freezing point. KNO3, Li3PO4, Na2SO4, SnCl4

###### FREE Expert Solution

Hey there! We have to arrange the solutions of KNO3, Li3PO4, Na2SO4, SnCl4 by their freezing points.

Freezing point depression is the decrease in freezing point of solution, when a solute is added to a solvent. It is calculated using this formula:

$\overline{){\mathbf{∆}}{{\mathbf{T}}}_{{\mathbf{f}}}{\mathbf{=}}{\mathbf{i}}{\mathbf{·}}{{\mathbf{K}}}_{{\mathbf{f}}}{\mathbf{·}}{\mathbf{m}}}$

Where:

ΔTf = change in freezing point

i = van ‘t Hoff factor

Kf =freezing point depression constant

m = molality

Since, all the solutions have equal concentrations, we just have to look at the van ‘t Hoff factor to determine the freezing point depression.

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###### Problem Details

Assuming equal concentrations, rank these aqueous solutions by their freezing point. From highest freezing point to lowest freezing point. KNO3, Li3PO4, Na2SO4, SnCl4