Problem: What is the enthalpy for reaction 1 reversed?reaction 1 reversed: CO2 (g) → CO (g) + 1/2 O2 (g)

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We are being asked to calculate the enthalpy for the reaction, ΔH°rxn

reaction 1 reversed: CO2 (g)  CO (g) + 1/2 O2 (g)


Recall the equation to calculate the enthalpy of the reaction

H°rxn =H°f, product -H°f, reactant


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Problem Details

What is the enthalpy for reaction 1 reversed?

reaction 1 reversed: CO2 (g) → CO (g) + 1/2 O2 (g)

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